Question

In $\Delta XYZ,\angle Y={90}^o,\angle Z=a^o,\angle X=(a+30{)}^o$ Find $\angle X$.

Answer 1

We have in $\Delta XYZ$,

$\angle X+\angle Y+\angle Z={180}^o$ [ Given]

or, $a^o+{30}^0+a^o+{90}^o={180}^o$

or, $2a^o={60}^o$

or, $a^o={30}^o$

or, $a^o+{30}^o={60}^o$

or, $\angle X={60}^o$.