In determination of acceleration due to gravity (g) using the formula T=2π√Lg the errors in measurement of and rare 1% and 2% respectively The Maximum percentage error in the value of g
The correct option is C 5%
T=2π√Lg
squaring both sides,
T2=4π2Lg
g=4π2LT3
As per rule,
Δgg=±[ΔLL+2(ΔTT)]
For percentage error,
Δgg×100%=±[ΔLL×100%+2(ΔTT×100%)]
Δgg×100%=±[1%+2×2%]
Δgg×100%=±[1%+4%]
Δgg×100%=±5%
Hence,
option (A) is correct answer.