In dihybrid cross, out of 16 plants obtained, the maximum number of different genotypes possible are

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Solution

The correct option is B 9
In any case where the parents are heterozygous for both traits (Say RrYy X RrYy), a ratio of 9:3:3:1 is obtained.
9 is the number for the two dominant traits, 3 is the number for a dominant / recessive combination, and only 1 individual will display both recessive traits. Another way to determine ratios is to calculate mathematically.
3/4 of all the offspring will have round seeds
3/4 of all the offspring will have yellow seeds
3/4 * 3/4 = 9/16 will have round yellow seeds
From the punnet square given below it is clear that there are 9 genotypes: RRYY, RRYy, RrYy, RrYY, Rryy, RRyy, rryy, rrYy and rrYY

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