In dihybrid cross, when $F_{1}$ plants (RrYy) are self-hybridised, the ratio of segregation of yellow and green in F $_{2}$ is

9:3:3:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:2:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3:1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1:1:1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 3:1
When pea plant with round shaped seeds with yellow colour seed (RRYY) is crossed with pea plant showing wrinkled shape with green cotyledons (rryy), the F $_{1}$ generation will have round shaped seeds with yellow colour seed (RrYy) progeny. When this plants are crossed, the F $_{2}$ generation will have progeny in the ratio of 9:3:3:1 as genotype and 3:1 as the phenotype.
Thus, the correct answer is option C.

Suggest Corrections

Similar questions

Q. Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridised then

F_{2}

- generation will show

Question 11
Two pea plants one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce F1 progeny that have round, yellow (RrYy) seeds. When F1 plants are selfed, the F2 progeny will have a new combination of characters. Choose the new combination of the following.

(i) Round, yellow
(ii) Round, green
(iii) Wrinkled, yellow
(iv)Wrinkled, green

(a) (i) and (ii)
(b) (i) and (iv)
(c) (ii) and (iii)
(d) (i) and (iii)