You visited us 1 times! Enjoying our articles? Unlock Full Access!

Preparations and Uses of Caustic Soda

In dilute alk...

Question

In dilute alkaline solution $M n O_{4}^{-}$ changes to:

M n O_{4}^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M n O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{M n}_{2} O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M n O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $M n O_{2}$
In alkaline solution, $M n O_{4}^{-} + 2 H_{2} O + 3 e \to M n O_{2} + 4 O H^{-}$

Suggest Corrections

Similar questions

M n O_{4}^{-}

K M n O_{4}

M n O_{4}^{2 -}, M n O_{2}, {M n}_{2} O_{3}

{M n}^{2 +}

K M n O_{4}

M n O_{4}^{2 -}, M n O_{2}, {M n}_{2} O_{3}

{M n}^{2 +}

△ G^{\circ}

M n O_{4}^{-} | M n O_{2}

x F

x

E_{M n O_{4}^{-} | M n^{2 +}}^{\circ} = 1.5 V; E_{M n O_{2} | M n^{2 +}}^{\circ} = 1.25 V

100

0.01 M

K M n O_{4}

100

H_{2} O_{2}

K M n O_{4}

100

H_{2} O_{2}

M n O_{4}^{⊝}

M n^{2 +}

M n O_{2}

Join BYJU'S Learning Program