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Standard XII

Physics

Size of Mirror

In displaceme...

Question

In displacement method, convex lens forms a real image of an object for its two different positions. If height of the images in two cases be $24 c m$ and $6 c m$ , then the height of the object is

3 c m

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36 c m

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6 c m

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12 c m

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Solution

The correct option is D $12 c m$
Given $H_{1} = 24 c m$ and $H_{2} = 6 c m$

In displacement method the height of the object is given as

$H = \sqrt{H_{1} H_{2}}$

$\Rightarrow H = \sqrt{24 \times 6} = \sqrt{144} = 12 c m$

Hence the correct answer is option (D).

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In displacement method, convex lens forms a real image of an object for its two different positions. If height of the images in two cases be 24cm and 6cm, then the height of the object is

The correct option is D 12cmGiven H1=24cm and H2=6cm In displacement method the height of the object is given as H=√H1H2 ⇒H=√24×6=√144=12cm Hence the correct answer is option (D).

In displacement method, convex lens forms a real image of an object for its two different positions. If height of the images in two cases be $24 c m$ and $6 c m$ , then the height of the object is

The correct option is D $12 c m$
Given $H_{1} = 24 c m$ and $H_{2} = 6 c m$

In displacement method the height of the object is given as

$H = \sqrt{H_{1} H_{2}}$

$\Rightarrow H = \sqrt{24 \times 6} = \sqrt{144} = 12 c m$

Hence the correct answer is option (D).