In - ABC - A-100- and AB - AC as shown in the figure Find - B and - C

We have #160;AB = AC ⇒∠ B=∠ C #160; Now #160; ∠ A+∠ B+∠ C=180^∘ ⇒∠ A+∠ B+∠ B= 180^∘ ⇒ 100^∘+2∠ B=180^∘ ⇒ 2∠ B=80^∘ ⇒∠ B=40^∘ ...

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In △ ABC ∠ ...

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In $△ A B C ∠ A = 100^{\circ}$ and AB = AC as shown in the figure Find $∠ B a n d ∠ C$

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