Question

In $\Delta ABC.AB=BC,AD\perp BC$ and $CE\perp AB$ Then,
$AD=CE$
If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

In $△$s ADC and ACE,
$\angle ACD=\angle CAE$ (Since, AB = BC, By Isosceles triangle property)
$AC=AC$ (Common)
$\angle ADC=\angle CEA={90}^{\circ }$ (Each ${90}^{\circ }$)
Thus, $△ADC\cong △CEA$