Question

In $\Delta ABC,AB$ is diameter of circumcircle. If H is orthocentre of $\Delta ABC,$ then AH divides BC in the ratio

• A. 2 : 1
• B. 3 : 1
• C. 2 : 3
• D. 1 : 1

Answer 1

The correct option is D 1 : 1

$\because AB$ is diameter of circle.

$\therefore \angle ACB=90°$

So, $△ACB$ is a right angle triangle.

$\therefore H$ is orthocentre at $C$.

So, $AH$ divides $BC$ in $1:1$ ratio.