In - ABC and - DBC-AC-BD and - ABC- BCD- 90 o- Then - ABC- DCB by the postulate

The correct option is B RHSIn #160; Δ ABC and #160; Δ DBC , ∠ ABC=∠ BCD AC=BD (Givenn) BC=BC (Common Side) Δ ABC≅Δ DCB WCB (By ...

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Standard IX

Mathematics

RHS Criteria for Congruency

In Δ ABC an...

Question

In $Δ A B C$ and $Δ D B C, A C = B D$ and $∠ A B C = ∠ B C D = 90^{o}$ . Then $Δ A B C ≅ Δ D C B$ by the postulate

SSS

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RHS

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Solution

The correct option is B RHS
In $Δ A B C$ and $Δ D B C$ ,
$∠ A B C = ∠ B C D$
$A C = B D$ (Givenn)
$B C = B C$ (Common Side)
$Δ A B C ≅ Δ D C B$ WCB (By RHS postulate)

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In ΔABC and ΔDBC,AC=BD and ∠ABC=∠BCD=90o. Then ΔABC≅ΔDCB by the postulate

The correct option is B RHSIn ΔABC and ΔDBC,∠ABC=∠BCDAC=BD (Givenn)BC=BC (Common Side)ΔABC≅ΔDCB WCB (By RHS postulate)

In $Δ A B C$ and $Δ D B C, A C = B D$ and $∠ A B C = ∠ B C D = 90^{o}$ . Then $Δ A B C ≅ Δ D C B$ by the postulate

The correct option is B RHS
In $Δ A B C$ and $Δ D B C$ ,
$∠ A B C = ∠ B C D$
$A C = B D$ (Givenn)
$B C = B C$ (Common Side)
$Δ A B C ≅ Δ D C B$ WCB (By RHS postulate)