In $Δ A B C, ∠ A = 12^{o}$ and $∠ C = 97^{o}$ . Arranging the sides (according to lengths) in ascending order, we get:

B C < A B < A C

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A B < A C < B C

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B C < A C < A B

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A B < B C < A C

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Solution

The correct option is C $B C < A C < A B$
In $Δ A B C, ∠ A = 12^{o}$ and $∠ C = 97^{o}$
$∴ ∠ B = 71^{o} (∵ ∠ A + ∠ B + ∠ C = 180^{o})$
Now arranging the angles in ascending order $∠ A < ∠ B < ∠ C$ .
Sides opposite to greater angle are greater in length and the angles and the opposite sides of a triangle have same relation.
Thus, arranging the sides in ascending order, we get $B C < A C < A B .$

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