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Question

In ΔABC,BD bisects angle B. If A=23B and B=3C, then BDC is:
376838_8a706f91ce4847f28d83025abcec023a.png

A
75o
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B
105o
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C
90o
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D
120o
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Solution

The correct option is B 105o
A=23BorB=32A
Again, A=23B=23×3CorC=A2
A+B+C=180o
Substituting the values of BandC
A+32A+A2=180o
orA=60o
B=32A=32×60o=90o
BDC=A+12B=60o+12×90o=105o
1028033_376838_ans_bbf6ff4d329c420abaf5faff2cc925db.png

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