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Question

In ΔABC prove that (ab)2cos2C2+(a+b)2sin2C2=c2

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Solution

Expanding L.H.S.=(a2+b22ab)cos2C2+(a2+b2+2ab)sin2C2
=a2+b2+2ab(sin2C2cos2C2)
=a2+b22abcosC
=a2+b2(a2+b2c2)=c2=R.H.S
Hence proved.

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