In ΔPQR,MN||QR and given that PM = 3 cm MQ = 8cm, QR = 32 then MN is (image)
In ΔPMNandΔPQR,∠Piscommon,∠PMN=∠PQRand∠PNM=∠PRQ[correspondinganglepairs] Hence the triangles are similar by AAA. So, PMPQ=MNQR⟹311=MN32⟹MN=8.7.