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Question

In division sum, the divisor is 4 times the quotient and twice the remainder if a and b are respectively the divisor and the divident, then :

A
4aa2a=3
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B
4b2aa2=3
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C
(a+1)2=4b
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D
a(a+2)b=4
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Solution

The correct option is D a(a+2)b=4
The relation between divisor, dividend, quotient and remainder is given by,
dividend = divisor × quotient + remainder

From given, we have
dividend =b
divisor =a
quotient =a4
remainder =a2

now we have,
b=a×a4+a2

4b=a2+2a
a(a+2)b=4

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