In ΔPQR, Q is a right angle, the lengths of PQ and PR are 8 cm and 17 cm, respectively. Find the length of QR.

13 cm

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14 cm

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15 cm

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16 cm

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Solution

The correct option is C 15 cm
ΔPQR is a right angled triangle.
∠Q = 90°, PQ = 8 cm, and PR = 17 cm

According to pythagoras theorem,
PQ² + QR² = PR²
⇒ (8)² + (QR)² = (17)²
⇒ 64 + (QR)² = 289
⇒ (QR)² = 225
⇒ QR = 15 cm

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In ΔPQR, Q is a right angle, the lengths of PQ and PR are 8 cm and 17 cm, respectively. Find the length of QR.

The correct option is C 15 cm ΔPQR is a right angled triangle. ∠Q = 90°, PQ = 8 cm, and PR = 17 cm According to pythagoras theorem, PQ² + QR² = PR² ⇒ (8)² + (QR)² = (17)² ⇒ 64 + (QR)² = 289 ⇒ (QR)² = 225 ⇒ QR = 15 cm

The correct option is C 15 cm
ΔPQR is a right angled triangle.
∠Q = 90°, PQ = 8 cm, and PR = 17 cm

According to pythagoras theorem,
PQ² + QR² = PR²
⇒ (8)² + (QR)² = (17)²
⇒ 64 + (QR)² = 289
⇒ (QR)² = 225
⇒ QR = 15 cm