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Question
In ΔPQR, S is any point on the side QR, then
In ΔPQR, S is any point on the side QR, then
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Solution
The correct option is A PQ + QR + RP > 2PS
In ΔPQS, PQ + QS > PS ¼(1)
In ΔPRS, RP + RS > PS ¼(2)
(Sum of any two sides of a triangle is greater than the third side)
Adding (1) and (2) you get
PQ + (QS + RS) + RP > 2PS
Or PQ + QR + RP > 2PS
PQ + QR + RP > 2PS
In ΔPQS, PQ + QS > PS ¼(1)
In ΔPRS, RP + RS > PS ¼(2)
(Sum of any two sides of a triangle is greater than the third side)
Adding (1) and (2) you get
PQ + (QS + RS) + RP > 2PS
Or PQ + QR + RP > 2PS
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