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Question

In driving the usual route to school Shyam computes the average speed for the trip to be 20 km/h. On the return trip along the same route, there is less traffic and the average speed is 40 km/h, What is
the average speed for Shyam's total trip ?

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Solution

Suppose the distance to school is d Ian. Then, Time taken to drive to school =DistanceSpeed=dkm20km/h=d20h Time taken in returning by. the same route =dkm40km/h=d40h Total time =d20h+d40h=2d+d40h=3d40h Average speed =DistanceTime=2dkm3d40h =2×403km/h=803km/h=26.66km/h=26.7km/h. (to 1 dp)

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