In Drosophila, the red-eye character is dominant over white eye character. When a homozygous red-eyed individual is crossed with a homozygous white-eyed individual, and individuals of $F_{1}$ generation are intercrossed, 12 individuals are produced. White-eyed individuals of these will be:

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Solution

The correct option is A
3

It is a monohybrid cross. Monohybrid cross produces progeny of $F_{2}$ generation in ratio 3:1 where 1 is the ratio of recessive progeny. Here in, the number of recessive white-eyed individuals can be found by:
Total number according to ratio = 3+1 = 4.
Total number of individuals produced actually = 12
Number of white-eyed individuals = $\frac{1}{4} \times 12 = 3$

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In Drosophila, the red-eye character is dominant over white eye character. When a homozygous red-eyed individual is crossed with a homozygous white-eyed individual, and individuals of F1 generation are intercrossed, 12 individuals are produced. White-eyed individuals of these will be:

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