Question

In each case, state True if the trinomial is a perfect square else state False. $a^2-10a+25$

If true then enter 11 and if false then enter 0

Answer 1

Given that,

$a^2-10a+25$

$=a^2-10a+5^2$

By Factorizing we get

$a^2-10a+25$,

Split $10a$ as:
$=a^2-5a-5a+25=a(a-5)-5(a-5)=(a-5)(a-5)$

i.e. it is a perfect square

$\therefore \text{answer is 1}$