In each of the following case divide the first polynomial by the second polynomial and express as Divident = Divisor ✕ quotient + Remainder.

(i) x³ $-$ 5x² + 4x + 8 ; x + 2

Open in App

Solution

Here, quotient = x² $-$ 7x + 18
and remainder = $-$ 28

$∴ x^{3} - 5 x^{2} + 4 x + 8 = (x + 2) (x^{2} - 7 x + 18) - 28$

Suggest Corrections

Similar questions

x^{3} - 5 x^{2} + 4 x + 8; x + 2

=

\times

+

x^{3} - 64; x - 4

Divide the first polynomial by the second polynomial in each of the following, Also, write the quotient and remainder.

(i) $3 x^{2} + 4 x + 5, x - 2$

(ii) $10 x^{2} - 7 x + 8, 5 x - 3$

(iii) $5 y^{2} - 6 y^{2} + 6 y - 1, 5 y - 1$

(iv) $x^{4} - x^{3} + 5 x, x - 1$

(v) $y^{4} + y^{2}, y^{2} - 2$

\times

x^{3} - 64; x - 4

5 x^{5} + 4 x^{4} - 3 x^{3} + 2 x^{2} + 2; x^{2} - x

Join BYJU'S Learning Program