Question

In each of the following, determine whether the given values are solutions of the given equation or not:

$x^2-3x+2=0,x=2,x=-1$

• A. $x=2$ is a solution but $x=-1$ is not a solution
• B. $x=2$ is not a solution but $x=-1$ is a solution
• C. $x=2$ and $x=-1$ both are not solution
• D. $x=2$ and $x=-1$ both are solution

Answer 1

The correct option is A $x=2$ is a solution but $x=-1$ is not a solution

$x^2-3x+2=0$

$\Rightarrow$ $x^2-2x-x+2=0$

$\Rightarrow$ $x(x-2)-1(x-2)=0$

$\Rightarrow$ $(x-2)(x-1)=0$

$\Rightarrow$ $x-2=0$ and $x-1=0$

$\therefore$ $x=2$ and $x=1$

Here, we can see the correct answer is option A