Question

In each of the following figure, find the value of x :

Answer 1

$y+y+{40}^o={180}^o$

$y={70}^o$

$x={40}^o+y$

(exterior angle)

$\Rightarrow x={110}^o$

$\angle x={180}^o-2\left({30}^o\right)={120}^o$

$\angle ACB={180}^o-{120}^o={60}^o$

$x+65+60={180}^o$

$x={55}^o$.