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Question

In each of the following, find the co-ordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation:
2a31=a2;154b7=2b13.

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Solution

First equation:
2a3 1= a2
2a3 a2 =1
On solving we get,
a=6
Second equation:
154b7 = 2b13
On cross - multiplying, we get,
4512b=14b7
b=2
Hence, required point =(a,b)=(6,2)

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