(i) Sum of the given digits = 6 + 7 + 1 + 9 = 23
The multiple of 9 which is greater than 23 is 27.
Therefore, the smallest required number = 27 − 23 = 4
(ii) Sum of the given digits = 6 + 6 + 7 + 8 + 4 = 31
The multiple of 9 which is greater than 31 is 36.
Therefore, the smallest required number = 36 − 31 = 5
(iii) Sum of the given digits = 5 + 3 + 8 + 8 = 24
The multiple of 9 which is greater than 24 is 27.
Therefore, the smallest required number = 27 − 24 = 3