Question

In each of the following questions, a series of number is given which follow certain rules. One of the number is missing. Choose the missing number from the alternatives given below and mark it on your answer-sheet as directed. $1,\frac{1}{3},\frac{1}{9},\frac{1}{27},\frac{1}{81},\frac{1}{243},$?

• A. $\frac{1}{729}$
• B. $\frac{1}{829}$
• C. $\frac{1}{749}$
• D. $\frac{1}{769}$

Answer 1

The correct option is A $\frac{1}{729}$

G.P series with common ratio $\frac{1}{3}$

$\therefore$, next term is $\frac{1}{243}\times \frac{1}{3}=\frac{1}{729}$