(a) 12525∗2
First adding all the digits of the given number.
∴1+2+5+2+5+∗+2=17+∗
For 12525∗2 to be divisible by 9, 17+∗ must be divisible by 9.
Again adding the digits of 1+7+∗
1+7+∗=8+∗, which must be equal to 9.
i.e., 8+∗=9
⇒∗=9−8=1.
If ∗=1,17+∗=17+1=18, which Is a multiple of 9.
∴1252512 is the required number.
(b) 251∗3373
Firstly add the digits of the given number.
i.e., 2+5+1+∗+3+3+7+3=24+∗, which must be a multiple of 9
Again adding the digits of 24+∗
i.e., 2+4+∗=6+∗ which must be equal to 9.
i.e., 6+∗=9
⇒∗=9−6
⇒∗=3
If ∗=3, then 24+∗=24+3=27, which is a multiple of 9.
∴25133373 is the required number.