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Question

In each of the following two polynomials, find the value of a, if x+a is a factor:

x3+ax22x+a+4

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Solution

Given: (x+a) is a factor of x3+ax22x+a+4

Let f(x)=x3+ax22x+a+4
(x+a) is a factor of x3+ax22x+a+4

f(a)=0 [Using factor theorem]

(a)3+a×(a)22×(a)+a+4=0

a3+a3+2a+a+4=0

3a+4=0

3a=4

a=43

Hence, the value of a=43

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