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Question

In each of the four situations of column - I, a stretched string or an organ pipe is given along with the required data. In case of strings the tension in string is T = 102.4 N and the mass per unit length of string is 1 g/m. Speed of sound in air is 320 m/s. Neglect end corrections. The frequencies of resonance are given in column - II. Match each situation in column - I with the possible resonance frequencies given in Column - II.

A
P - 1 ; Q - 3 ; R - 2 ; S - 4
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B
P - 1 ; Q - 4 ; R - 3 ; S - 2
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C
P - 3 ; Q - 2 ; R - 4 ; S - 1
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D
P - 2 ; Q - 4 ; R - 1 ; S - 3
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Solution

The correct option is B P - 1 ; Q - 4 ; R - 3 ; S - 2
(P) The fundamental frequency in the string fixed from both ends,
f0=Tμ2=102.41×103×12×0.5Hz=320 Hz.
So, possible resonance frequencies are fP=320 Hz,640 Hz,960 Hz ...

(Q) The fundamental frequency in the string free from one end,
f0=Tμ4=3204×0.5=160 Hz
So, possible resonance frequencies are
fQ=160 Hz,480 Hz,800 Hz ...

(R) The fundamental frequency in organ pipe open at both ends is,
f0=v2=3202×0.5=320 Hz
So, possible resonance frequencies are
fR=320 Hz,640 Hz,960 Hz...

(S) The fundamental frequency in one end open organ pipe is
f0=v4=3204×0.5=160 Hz
So, possible resonance frequencies are
fS=160Hz,480 Hz,800 Hz...

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