You visited us 2 times! Enjoying our articles? Unlock Full Access!

Variation of G Due to Height and Depth

In each part ...

Question

In each part of this question a statement is followed by four choices. In each part one or more choice (s) is/are correct. Select the correct choice (s) in each case and write down the corresponding letter (s) A, B, C, D in your book against, the sub-question number. In your answers, the sequence of the sub-question should be the same as in the question paper. For each sub-question, marks will be awarded only if the correct and only correct choice (s) is/are written. The magnitudes of the gravitational field at distances $r_{1} a n d r_{2}$ from the centre of a uniform sphere of radius R and mass M are $F_{1} a n d F_{2}$ respectively, then

\frac{F_{1}}{F_{2}} = \frac{r_{1}}{r_{2}} i f r_{1} < R a n d r_{2} < R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{F_{1}}{F_{2}} = \frac{r_{2}^{2}}{r_{1}^{2}} i f r_{1} > R a n d r_{2} > R

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{F_{1}}{F_{2}} = \frac{r_{1}}{r_{2}} i f r_{1} > R a n d r_{2} > R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{F_{1}}{F_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}} i f r_{1} < R a n d r_{2} < R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{F_{1}}{F_{2}} = \frac{r_{2}^{2}}{r_{1}^{2}} i f r_{1} > R a n d r_{2} > R$
Option $B$
Using the law of Newton's gravitational force we can formulate that
$F = \frac{G M m}{r^{2}}$
where $F =$ Force quantity
$M =$ mass of the large object
$m =$ mass of the smaller object
$r =$ radius in between two object
If $r_{1} > R r_{2} > R$
Now
$\frac{F_{1}}{F_{2}} = \frac{r_{2}^{2}}{r_{1}^{2}}$

Suggest Corrections

Similar questions

Q. The magnitudes of the gravitational force at distances

r_{1}

and

r_{2}

from the centre of a uniform sphere of radius

R

and mass

M

are

F_{1}

and

F_{2}

respectively. Then

The magnitude of the gravitational force at distance $r_{1}$ and $r_{2}$ from the centre of a uniform sphere of radius R and mass M are $F_{1}$ and $F_{2}$ respectively. Then,

Q. The magnitudes of the gravitational field at distances

r_{1}

and

r_{2}

from the centre of a uniform sphere of radius

R

and mass

M

are

F_{1}

and

F_{2}

, respectively. Then.

Q. The magnitude of the gravitational field at distance

r_{1}

and

r_{2}

from the centre of a uniform sphere of radius

R

and mass

M

are

F_{1}

and

F_{2}

respectively then

Q. The magnitudes of the gravitational force at distances

r_{1}

and

r_{2}

from the centre of a uniform sphere of radius R and mass M are

F_{1}

and

F_{2}

respectively. Then

Join BYJU'S Learning Program

The correct option is B F1F2=r22r21 ifr1>Randr2>ROption BUsing the law of Newton's gravitational force we can formulate thatF=GMmr2where F= Force quantityM= mass of the large objectm= mass of the smaller objectr= radius in between two objectIf r1>Rr2>RNowF1F2=r22r21