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Question

In electrolysis of very dilute NaOH solution using platinum electrodes:

A
H2 is evolved at cathode
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B
H2 is produced at anode
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C
Na is obtained at cathode
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D
O2 is produced at anode
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Solution

The correct options are
A H2 is evolved at cathode
D O2 is produced at anode
In aqueous NaOH solution, on electrolysis, we have the reduction potential of H+ is much more than Na+, so the reaction takes place as;

At anode: 4OH2H2O+O2+4e

At cathode: 4H++4e2H2

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