Question

In end on and broadside on position of a deflection magnetometer, if ${\theta }_1$ and ${\theta }_2$ are the deflections produced by short magnets at equal distances, then $\tan {\theta }_1/\tan {\theta }_2$ is

• A. $2:1$
• B. $1:2$
• C. $1:1$
• D. None of these

Answer 1

The correct option is A $2:1$

$B=B_{H}tan\theta$

End On, Tan A: $\frac{{\mu }_{0}2Md}{4\pi (d^2-l^2{)}^2}$

Tan B: $\frac{{\mu }_{0}M}{4\pi (d^2+l^2{)}^{3/2}}$

$\frac{tan{\theta }_1}{tan{\theta }_2}=B_1:B_2=2:1$ $(l<<d)$