Question

In equation $H_{2}S+2HN{O}_3\to 2H_{2}O+2N{O}_2+S$

Equivalent weight of $H_{2}S$ is

• A. $68$
• B. $34$
• C. $17$
• D. $16$

Answer 1

Answer: (C)

$17$

$H_2\stackrel{-2}{S}\to \stackrel{0}{S}+2e$

Equivalent weight $=\frac{Mol.wt.}{n_f}=\frac{Mol.wt.}{2}=\frac{34}{2}=17$