In every gram of gold, a goldsmith mixes 0.20 grams of silver and 0.10 grams of copper. What percent of gold is present?

75%

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60%

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70%

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80%

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Solution

The correct option is C 70%
$∵$ 1g = 1000 mg

Given, 1 g of gold contains
0.20g of silver = 200 mg

and, 0.10 g of copper = 100 mg

So, amount of gold
= 1000 - (200 + 100)
= 700 mg

Percentage of gold used

= $\frac{700}{1000} \times$ 100

=70%

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In every gram of gold, a goldsmith mixes 0.20 grams of silver and 0.10 grams of copper. What percent of gold is present?

The correct option is C 70%∵ 1g = 1000 mg Given, 1 g of gold contains 0.20g of silver = 200 mg and, 0.10 g of copper = 100 mg So, amount of gold = 1000 - (200 + 100) = 700 mg Percentage of gold used = 7001000× 100 =70%

The correct option is C 70%
$∵$ 1g = 1000 mg

Given, 1 g of gold contains
0.20g of silver = 200 mg

and, 0.10 g of copper = 100 mg

So, amount of gold
= 1000 - (200 + 100)
= 700 mg

Percentage of gold used

= $\frac{700}{1000} \times$ 100

=70%