In expressing a length $81.472 k m$ as nearly as possible with three significant digits, the percent error is

0.34 %

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0.034 %

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0.0034 %

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0.0038 %

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Solution

The correct option is D $0.034 %$
$81.472 k m = 81472$ meters $= 81500$ meters with three significant digits.
$∴ E r r o r % = \frac{81500 - 81472}{81472} \times 100 = 0.034 %$

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