In expressing a length of 81.472 km as nearly as possible with three significant digits, find the percentage error.

0.014 %

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0.018 %

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0.024 %

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0.034 %

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Solution

The correct option is D 0.034 %
Error= $(81.5 - 81.472) K m . = .028$
So required percentage= $\frac{.028}{81.472} \times 100 = .034$

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In expressing a length of 81.472 km as nearly as possible with three significant digits, find the percentage error.

The correct option is D 0.034 %Error=(81.5−81.472)Km.=.028So required percentage=.02881.472×100=.034

The correct option is D 0.034 %
Error= $(81.5 - 81.472) K m . = .028$
So required percentage= $\frac{.028}{81.472} \times 100 = .034$