Question

In ${\left[Fe\right(NH}_3{)}_6{]Cl}_3$ the number of covalent bonds is:

• A. 3
• B. 6
• C. 9
• D. 18

Answer 1

The correct option is D 18

In $\left[Fe{\left(N{H}_3\right)}_6\right]{Cl}_3$, there are covalent bonds.

In $\left[Fe{\left(N{H}_3\right)}_6\right]{Cl}_3$, each $N{H}_3$ has 3 covalent bonds. There are 6 $N{H}_3$ in the given compound. So, the number of covalent bonds=6$\times$3=18 bonds

Total number of bonds in $\left[Fe{\left(N{H}_3\right)}_6\right]{Cl}_3$ is 18.