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Assigning Oxidation Numbers

In FeCr2O4,...

Question

In $F e C r_{2} O_{4}$ , the oxidation number of fe and Cr are:

A

+ 2 and + 3

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B

0 and +2

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C

+ 2 and +6

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D

2 and 5

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Solution

The correct option is A + 2 and + 3
Chromium is found in nature principally as the chromite ore FeCr2O4 in which chromium is in the $+ 3$ state.

Oxidation state of

Cr is $3 +$

Oxygen is $2 -$

So, net charge of $C r_{2} O_{4} (3 \times 2 - 4 \times 2) = + 2$

So, Oxidation state of Fe is $2 + .$

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F e C r_{2} O_{4}

the oxidation numbers of Fe and Cr are:

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