In Fehling's or Benedict's solution, a reducing sugar causes conversion of
A
Ferric to ferrous state
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Ferrous to ferric state
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Cuprous to cupric state
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Cupric to cuprous state
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D Cupric to cuprous state
Saccharides having free aldehyde and ketone groups are known as reducing sugar. Benedict's or Fehling's solution is used to identify the reducing sugar. The sugar can reduce cupric ions of Benedict's or Fehling's solution to cuprous ion. The solution contains a blue colour alkaline solution of copper sulphate. Reducing sugar changes into insoluble reddish cuprous oxide. Thus, the correct answer is D.