In $F e S O_{4}$ . $7 H_{2} O$ , $H_{2} O$ represents:

molar mass

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molecular weight

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molar weight

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water of crystallisation

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Solution

The correct option is B water of crystallisation
Water of crystallisation is the fixed number of water molecules present in one formula unit of a salt. For example, chemical formula for hydrated copper sulphate is Cu SO4. 5H2O i.e, five water molecules are present in one formula unit of copper sulphate. Thus, option $D$ is correct

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Similar questions

K_{2} C r_{2} O_{7}

F e S O_{4}

K_{2} C r_{2} O_{7} + 7 H_{2} S O_{4} + 6 F e S O_{4} \to C r_{2} (S O_{4})_{3} + K_{2} S O_{4} + 3 F e_{2} (S O_{4})_{3} + 7 H_{2} O

F e S O_{4} \cdot 7 H_{2} O

F e {S O}_{4} \cdot {({N H}_{4})}_{2} \cdot {S O}_{4} \cdot 6 H_{2} O

F e {S O}_{4} \cdot 7 H_{2} O

K M n O_{4}

(F e S O_{4} \cdot 7 H_{2} O)

F e S O_{4} ∙ 7 H_{2} O

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