In few climates- the range of temperatures may go to as much as 20 - Celsius in a single day- How much can these climates vary measured in degree Fahrenheit- F- 9 - 5 C-32

The correct option is D 68 ^∘F We know that #160; F=95C+32 Then Fahrenheit temp at 20^0 is F=95C+32 F=95× 20+32=36+32=68^0 ...

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Standard XII

Physics

Convection

In few climat...

Question

In few climates, the range of temperatures may go to as much as $20^{\circ}$ Celsius in a single day. How much can these climates vary measured in degree Fahrenheit? ( $F = \frac{9}{5} C + 32$ )

20^{\circ} F

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36^{\circ} F

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62^{\circ} F

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68^{\circ} F

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Solution

The correct option is D $68^{\circ} F$
We know that $F = \frac{9}{5} C + 32$
Then Fahrenheit temp at $20^{0}$ is
$F = \frac{9}{5} C + 32$
$F = \frac{9}{5} \times 20 + 32 = 36 + 32 = 68^{0}$

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Similar questions

A solution is to be kept between $68^{\circ} F$ and $77^{\circ} F$ . What is the range of temperature in degree Celsius (C) if the Celsius /Fahrenheit (F) convension formula is given by $F = \frac{9}{5} C + 32$ ?

A solution is to be kept between 68°F and 77°F. What is the range in temperature in degree Celsius (C) if the Celsius/Fahrenheit (F) conversion formula is given by

Q. A solution is to be kept between

68^{o} F

and

77^{o} F

. What is the range in temperature in degree Celsius (C) if the Celsius / Fahrenheit (F) conversion formula is given by

F = \frac{9}{5} C + 32 ?

Q. A solution is to be kept between

68^{\circ} F

and

77^{\circ} F

. What is the range in temperature in degree Celsius (C) if the Celcius / Fahrenheit (F) conversion formula is given by

F = \frac{9}{5} C + 32

A solution is to be kept between $86^{\circ} a n d 95^{\circ} F$ .What is the range of temperature in degree Celsius,if the Celsius(C)/Fahrenheit (F) conversion formula is given by $F = \frac{9}{5} C + 32.$ .

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In few climates, the range of temperatures may go to as much as 20∘ Celsius in a single day. How much can these climates vary measured in degree Fahrenheit? (F=95C+32)

The correct option is D 68∘FWe know that F=95C+32Then Fahrenheit temp at 200 isF=95C+32F=95×20+32=36+32=680

In few climates, the range of temperatures may go to as much as $20^{\circ}$ Celsius in a single day. How much can these climates vary measured in degree Fahrenheit? ( $F = \frac{9}{5} C + 32$ )

The correct option is D $68^{\circ} F$
We know that $F = \frac{9}{5} C + 32$
Then Fahrenheit temp at $20^{0}$ is
$F = \frac{9}{5} C + 32$
$F = \frac{9}{5} \times 20 + 32 = 36 + 32 = 68^{0}$