In fig. 1, AOB is a straight line, the value of $x$ is :

60^{\circ}

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30^{\circ}

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20^{\circ}

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40^{\circ}

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Solution

The correct option is B $30^{\circ}$
$A O B$ is a line
$30^{\circ} + 90^{\circ} + 2 x = 180^{\circ} 2 x = 180^{\circ} - 120^{\circ} 2 x = 60^{\circ} \Rightarrow x = 30^{\circ}$

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Similar questions

In given below Fig. $A O B$ is a straight line and the ray $O C$ stands on it. The value of $x$ is
(a) $16$
(b) $26$
(c) $36$
(d) $46$

In the given figure, AOB is a straight line. The value of x is

(a) 12

(b) 15

(d) 25

In the figure, the value of x that will make AOB, a straight line is

A O B

x

∠ A O C = 60^{0}

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