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Question

In fig-10, ABC and ADC are two right triangles with common hypotenuse AC. Show that, CAD=CBD .
1397190_84999898c6504b4a8a6be9f420ba71f3.jpg

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Solution

The triangles formed on diameter of circle and the vertex on the circle have same area and same height

AC||BD

and AD is transversal

The Interior Alternate angles are equal

CAD=ADB




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