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Question

In Fig. 16.21, the bisectors of ∠A and ∠B meet at a point P. If ∠C = 100° and ∠D = 50°, find the measure of ∠APB.

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Solution

A+B+C+D=360°A+B+100°+50°=360°A+B=210° ...(i)In APB, we have:12A+12B+APB=180°APB=180°-12A+BFrom (i), we get:APB=180°-12×210° APB=75°

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