In fig.16, AD = DC and AB = BC
(i) Is ΔABD ≅ ΔCBD?
(ii) State the three parts of matching pairs you have used to answer (i).
Yes ΔABD ≅ΔCBD by the SSS criterion.
SSS criterion is two triangles are congruent if the three sides of triangle are respectively equal to the three sides of the other triangle.
Hence ΔABD ≅ΔCBD
(ii) We have used the three conditions in the SSS criterion as follows:
AD = DC
AB = BC and
DB = BD