Question

In Fig. 19, ∆ ABC is isosceles with AB = AC, D is the mid-point of base BC.
(i) Is ∆ ADB ≅ ∆ ADC?
(ii) State the three pairs of matching parts you use to arrive at your answer.

Answer 1

We have AB = AC.
Also since D is the midpoint of BC, BD = DC.
And AD = DA.
Therefore by SSS condition, $△ABD\cong △ADC$.

We have used AB, AC : BD, DC and AD, DA.