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Question

In fig 2.57, if AB || DE BAC = 35° and CDE = 53°, find DCE.

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Solution

Given: AB DE Also, BAC= CED = 35° (Alternate angles) In DCE, we have:DCE +CDE+CED =180° (Angle sum property)DCE +53°+35° =180° DCE = 92°

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