In Fig.2, PQ and PR are two tangents to a circle with centre O. If ∠QPR=46∘, then ∠QOR equals :
Given : ∠QPR=46∘
PQ and PR are tangents.
Therefore, the radius drawn to these tangents will be perpendicular to the tangents.
So, we have OQ⊥PQ and OR⊥RP.
⇒∠OQP=∠ORP=90∘
So, in quadrilateral PQOR, we have
∠OQP+∠QPR+∠PRO+∠ROQ=360∘
⇒90∘+46∘+90∘+∠ROQ=360∘
⇒∠ROQ=360∘−226∘=134∘
Hence, the correct option is B.