In Fig. 25, find ∠x. Further find ∠BOC, ∠COD and ∠AOD.

Open in App

Solution

$∠ A O D + ∠ D O C + ∠ C O B = 180 ° (L i n e a r p a i r) (x + 10) ° + x ° + (x + 20) ° = 180 ° 3 x + 30 ° = 180 ° 3 x = 180 ° - 30 ° 3 x = 150 ° x = \frac{150 °}{3} = 50 °$
$∠ B O C = x + 20 ° = 50 ° + 20 ° = 70 ° ∠ C O D = x = 50 ° ∠ A O D = x + 10 ° = 50 ° + 10 ° = 60 °$

Suggest Corrections

Similar questions

In the figure, find x, further find $∠ B O C, ∠ C O D$ and $∠ A O D$ .

∠ A O B = 45^{o}, ∠ B O C = 30^{o}

∠ A O D = 110^{o}

C O D

B O D

∠ A O D = 120, ∠ B O C = 110

∠ C O D

∠ A O B = ∠ B O C = ∠ C O D = 38^{\circ}

∠ A O C

∠ A O D

Join BYJU'S Learning Program