Question

In Fig. 3, AD = 4 cm, BD = 3 cm and CB = 12 cm, then cot θ equals

(a) $\frac{3}{4}$

(b) $\frac{5}{12}$

(c) $\frac{4}{3}$

(d) $\frac{12}{5}$

Answer 1

In Fig 3, if we have

AD = 4 cm,

BD = 3 cm, and

CB = 12 cm, then

cot θ = ?

We have the following diagram

If we apply Pythagoras theorem in triangle ADB, we get

Now,

Hence the correct option is